Solve for $x : x^{2} + 6 x - 27 = 0$

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Solution

Now,
$x^{2} + 6 x - 27 = 0$
or, $x^{2} + 9 x - 3 x - 27 = 0$
or, $x (x + 9) - 3 (x + 9) = 0$
or, $(x + 9) (x - 3) = 0$
or $x = - 9, 3$ .

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x^{2} + 6 x - 27 = 0

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