The correct option is A −1
{6,−1}: Distribute the multiplication by x. Note that, when you cancel the x in the denominator, the quantity 5x+6 is implicitly enclosed in parenthesis!
x(x−5x+6x)=0
x2−(5x+6)=0
x2−5x−6=0
(x−6)(x+1)=0
x=6 or −1
Note also that the value 0 is impossible for x, because x is in a denominator by itself in the original equation. You are not allowed to divide by 0. Do not look at the product in the original equation and deduce that x=0 is a solution.