Question

Solve for $x$:

$x{\sec }^2{45}^o.cose{c}^2{45}^o+2(\sin {60}^o+\sin {30}^o)=\tan {60}^o$

Answer 1

Given,

$x{\sec }^2{45}^o.cose{c}^2{45}^o+2(\sin {60}^o+\sin {30}^o)=\tan {60}^o$

or, $x.2.2+2(\frac{\sqrt{3}}{2}+\frac{1}{2})=\sqrt{3}$

or, $4x+(\sqrt{3}+1)=\sqrt{3}$

or, $x=-\frac{1}{4}$.