Consider the given complex equation,
cosx+isiny=0+i
Now,
cosx=0 …… (1)
siny=1 …. (2)
From equation 1st,
cosx=0
cosx=cosπ2
x=π2
From equation 2nd,
siny=1
siny=sinπ2
y=π2
So, x=π2 andy=π2
Hence, this is the answer.
(cosx+isinx)(cosy+isiny)(cotu+i)(1+itanv)