Question

Solve for $y$

$3y^2+7y+1=0$

Answer 1

$3y^2+7y+1=0$

Using quadratic formula,

$y=\frac{-7\begin{array}{c}\pm \end{array}\sqrt{49-4\times 3\times 1}}{2\times 3}=\frac{-7\begin{array}{c}\pm \end{array}\sqrt{37}}{6}$

$y_1=\frac{-7+\sqrt{37}}{6}$ and $y_2=\frac{-7-\sqrt{37}}{6}$