wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve for y in the following equation:
y2/32y1/3=15

A
-27 and 125
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
-125 and 27
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-125 and -27
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of These
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A -27 and 125
We have,
y232y13=15
Let y13=p
So, we get,
p22p=15
p22p15=0
p25p+3p15=0
p(p5)+3(p5)=0
(p5)(p+3)=0
p=5 or p=3
y13 = 5 or y13=3
y=53=125 or y=(3)3=27
So, correct option is a.

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon