Solve for y-y -4 1-4-7A- 2 3-14B- 3 3-4C- 2 1-4D- 2 3-4

The correct option is D 23/4y + 41/4 = 7 = y + 17/4 = 7 Subtract 17/4 from both sides of the equation: =y + 17/4 17/4 = 7 17/4 = y = 7 17/4 = y = 28 17/4 ...

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Byju's Answer

Standard VI

Mathematics

Solution of an Equation

Solve for y:y...

Question

Solve for y:
$y$ + $4 \frac{1}{4} = 7$

2 \frac{3}{14}

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3 \frac{3}{4}

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2 \frac{1}{4}

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2 \frac{3}{4}

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Solution

The correct option is D $2 \frac{3}{4}$
$y$ + $4 \frac{1}{4} = 7$
= $y$ + $\frac{17}{4} = 7$
Subtract $\frac{17}{4}$ from both sides of the equation:
= $y$ + $\frac{17}{4} - \frac{17}{4} = 7 - \frac{17}{4}$
= $y$ = $7 - \frac{17}{4}$
= $y$ = $\frac{28 - 17}{4}$ = $\frac{11}{4}$
= $y$ = $2 \frac{3}{4}$

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Solve for y: y + 414=7

The correct option is D 234y + 414=7 = y + 174=7 Subtract 174 from both sides of the equation: =y + 174−174=7−174 = y = 7−174 = y = 28−174 =114 = y = 234

Solve for y:
$y$ + $4 \frac{1}{4} = 7$