Question

Solve $\frac{1}{2}\left(\frac{3x}{5}+4\right)\ge \frac{1}{3}\left(x-6\right)$.

Answer 1

$Given:$ $\frac{1}{2}\left(\frac{3x}{5}+4\right)\ge \frac{1}{3}\left(x-6\right)$
$\Rightarrow 3(\frac{3x}{5}+4)\ge 2(x-6)$
$\Rightarrow \frac{9x}{5}+12\ge 2x-12$
$\Rightarrow 12+12\ge 2x-\frac{9x}{5}$
$\Rightarrow 24\ge \frac{x}{5}$
$\Rightarrow x\le 120$
$Solutionset$ = ($-\infty ,120$]