Solve-1-3-5-6-9-18-2-9

The correct option is B 5/36 Given, 1/3 (5/6×9/18)+2/9 = 1/3 (15/36)+2/9 [∵ Product of two fractions a/b and c/d is equal to a × c/b × d] (Using BOD ...

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Byju's Answer

Standard VI

Mathematics

Equivalent Fractions

Solve:1/3-5/6...

Question

Solve:

$\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}$

4/36

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5/36

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6/36

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7/36

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Solution

The correct option is B
5/36

Given, $\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}$
= $\frac{1}{3} - (\frac{15}{36}) + \frac{2}{9}$ [ $∵$ Product of two fractions $\frac{a}{b}$ and $\frac{c}{d}$ is equal to $\frac{a \times c}{b \times d}$ ] (Using BODMAS)

= $\frac{1}{3} - \frac{15}{36} + \frac{2}{9}$

Taking LCM of denominators, $\frac{12 - 15 + 8}{36} = \frac{5}{36}$ [LCM of 3, 36, and 9 = 36]

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Similar questions

Solve $\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}$ .

Q. Solve:

\frac{6 x - 2}{9} + \frac{3 x + 5}{18} = \frac{1}{3}

$\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}$

Q. Solve for x :

\frac{6 x - 2}{9} + \frac{3 x + 5}{18} = \frac{1}{3} .

Q. Solve equation

∣ ∣ ∣ ∣ \begin{matrix} 5 & 6 & 1 6 & 4 & 5 2 & 3 & - 9 \end{matrix} ∣ ∣ ∣ ∣ + ∣ ∣ ∣ ∣ \begin{matrix} x & 4 & 6 2 & 3 & - 9 5 & 6 & - 1 \end{matrix} ∣ ∣ ∣ ∣

= ∣ ∣ ∣ ∣ \begin{matrix} 2 & 3 & - 9 2 x - 1 & - 8 & - 11 5 & 6 & 1 \end{matrix} ∣ ∣ ∣ ∣

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Solve: 13−(56×918)+29

The correct option is B 5/36 Given, 13−(56×918)+29 = 13−(1536)+29 [∵ Product of two fractions ab and cd is equal to a×cb×d] (Using BODMAS) = 13−1536+29 Taking LCM of denominators, 12−15+836=536 [LCM of 3, 36, and 9 = 36]

Solve:

$\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}$