Solve :1015+515
Solve :1015+515:
Given,1015+515
Take the LCM of denominators i.e. 15
10+515=1515=1
Hence,the required answer is 1.
Solve : 15−2(2x−1)<15,x ϵ Z
Find the product : 112×56×815×34
Observe the patterns and fill in the blanks:
116+9=116+10-1=115+1063×5=63×102=630×12
63×15=63×302=630×32
63×25=63×502=630×52
63×35=63×702=630×_______________
63×45=63×902=630×_______________
116+99=116+100-1=115+100