Question

Solve: $\frac{-104x^3{y}^3{z}^3}{-13xyz}$

• A. $-8x^2{y}^2{z}^2$
• B. $-8xyz$
• C. $8x^2{y}^2{z}^2$
• D. $8x^3{y}^3{z}^3$

Answer 1

The correct option is C $8x^2{y}^2{z}^2$

$\frac{-104x^3{y}^3{z}^3}{-13xyz}$
= $8x^{3-1}{y}^{3-1}{z}^{3-1}$ $(\frac{104}{13}=8)$
= $8x^2{y}^2{z}^2$