Question

Solve:

$\frac{{12}^3\times 9^2\times 4}{6^4\times 8^2\times 8}.$

Answer 1

$\frac{{12}^3\times 9^2\times 4}{6^4\times 8^2\times 8}$

$=\frac{{12}^3\times 9^2\times 4}{6^3\times 2^3\times 2\times 8^2}$

$=\frac{{12}^3\times 9^2\times 4}{{12}^3\times 2\times 8^2}$

$=\frac{9^2\times 2}{8^2}$

$=\frac{81}{32}$.