Question

Solve: $\frac{15}{x}$ +$\frac{7}{y}$ = 8,$\frac{30}{x}$+$\frac{21}{y}$ = 18

• A.
  x = 3, y = $\frac{7}{3}$
• B.
  x = 2, y = 7
• C.
  x = $\frac{5}{2}$ y = $\frac{7}{2}$
• D. x = 5, y = $\frac{7}{5}$
• E. Not possible

Answer 1

The correct option is C

x = $\frac{5}{2}$ y = $\frac{7}{2}$
$\frac{15}{x}$ + $\frac{7}{y}$ = 8 $\Rightarrow$ $\frac{30}{x}$ + $\frac{14}{y}$ = 16 ....... (1)
$\frac{30}{x}$ + $\frac{21}{y}$ = 18 .......(2)
Subtracting (1) from 2, we get $\frac{7}{y}$ = 2
$\Rightarrow$ y = $\frac{7}{2}$
Substituting the value of y in either of the equations, we get x = $\frac{5}{2}$