Solve: $\frac{3 x + 3}{3} = 7$

x = 7

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x = 6

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x = 8

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x = 9

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Solution

The correct option is B
x = 6

$\frac{3 (x + 1)}{3} = 7 x + 1 = 7 x = 6$

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Similar questions

Solve: $\frac{3 x + 3}{3} = 7$

x^{3} + 3 x^{2} + 3 x + 7 = 0

\frac{1}{3^{x}} + \frac{2}{2^{y}} = 3

\frac{4}{3^{x}} + \frac{3}{2^{y}} - 7 = 0

\sqrt{3 x + 3} + \sqrt{3 x - 2} = 7

\frac{x + 3}{x + 2} = \frac{3 x - 7}{2 x - 3}

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