The correct option is C x=3,y=−1
Given system of equations are:
49x+13y=1 ... (1)
5x+2y=13 ... (2)
From equation 1 will get:
4x+3y=9
Now subtracting eq1 and eq2
4x+3y=9
5x+2y=13
First multiply eq1 from 2 and eq2 from 2 will get:
8x+6y=18
15x+6y=39
now will subtract the equation
⇒8x+6y=18
−15x−6y=−39
⇒−7x=−21
⇒x=3
now substituting x = 3 in eq 2
⇒15(3)+6y=39
⇒45+6y=39
⇒6y=39−45
⇒6y=−6
⇒y=−1
⇒x=3,y=−1