Solve:
$\frac{5}{8} + \frac{2}{8} - \frac{4}{8}$

$\frac{3}{8}$

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$\frac{4}{8}$

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$\frac{6}{8}$

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1 $\frac{3}{8}$

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Solution

The correct option is A
$\frac{3}{8}$

When we add or subtract like fractions the numerator of the fractions is added or subtracted and the denominator remains the same.

$\frac{5}{8} + \frac{2}{8} - \frac{4}{8} = \frac{(5 + 2 - 4)}{8} = \frac{(7 - 4)}{8} = \frac{3}{8}$

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Similar questions

(- 2) + 8 + (- 4)

2 + 4 + 8 = ?

(2^{- 2})^{- 2} \times (4^{- 2})^{- 4} \times (8^{- 2})^{4}

\frac{46}{2} - \frac{8}{2} + \frac{3}{4} = \frac{8}{2} \times x

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