The correct option is A x=4, y=5
If we substitute 1x−1 as p and 1y−2 as q in the given equations. (As x≠1,y≠2)
We get the equations as
5p+q=2
6p−3q=1
Now, we can solve the pair of equation by method of elimination.
15p+3q=6
6p−3q=1
On adding both the above equations, we get
p=13
Now by substituting the value in one of the equation we find q=13
As we have assumed p=1x−1
Therefore, p=1x−1=13
x=4
SImilarly we assumed q=1y−2
Hence 1y−2=13
y−2=3
Thus x=4 and y=5