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Question

Solve: cos2 θ3 cos θ+2sin2 θ=2 [4 MARKS]

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Solution

Formula: 2 Marks
Proof: 2 Marks

Givencos2 θ3 cos θ+2sin2 θ=2cos2 θ3 cos θ+2=2sin2 θcs2 θ3 cos θ+2=2(1cos2 θ)cos2 θ3 cos θ+22+2cos2 θ=03cos2 θ3 cos θ=03 cos θ(cos θ1)=0Either 3 cos θ=0 or cos θ1=0cos θ=0 or cos θ=1cos θ=cos 90 or cos θ=cos 0θ=90 or θ=0

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Range of Trigonometric Ratios from 0 to 90
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