Solve- cos 40-sin 50-1-2cos 35-sin 55-

cos 40^∘sin 50^∘=cos (90^∘ 50^∘)sin 50^∘=sin 50^∘sin 50^∘=1 cos 35^∘sin 55^∘=cos (90^∘ 55^∘)sin 55^∘=sin 55^∘sin 55^∘=1 cos 40^∘sin 50^∘ 12 ...

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Sin(A+B)Sin(A-B)

Solve: cos 4...

Question

Solve:
$\frac{cos 40^{\circ}}{sin 50^{\circ}} - \frac{1}{2} (\frac{cos 35^{\circ}}{sin 55^{\circ}})$

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Solution

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(i) ${(\frac{s i n 49^{o}}{c o s 41^{o}})}^{2} + {(\frac{c o s 41^{o}}{s i n 49^{o}})}^{2}$

(ii) $c o s 48^{o} - s i n 42^{o}$

(iii) $\frac{c o t 40^{o}}{t a n 50^{o}} - \frac{1}{2} (\frac{c o s 35^{o}}{s i n 55^{o}})$

(iv) ${(\frac{s i n 27^{o}}{c o s 63^{o}})}^{2} + {(\frac{c o s 63^{o}}{s i n 27^{o}})}^{2}$

(v) $\frac{t a n 35^{o}}{t a n 55^{o}} + \frac{c o t 78^{o}}{t a n 12^{o}} - 1$

(vi) $\frac{s e c 70^{o}}{c o s e c 20^{o}} + \frac{s i n 59^{o}}{c o s 31^{o}}$

(vii) $c o s e c 31^{o} - s e c 59^{o}$

(viii) $(s i n 72^{o} + c o s 18^{o}) (s i n 72^{o} - c o s 18^{o})$

(ix) $s i n 35^{o} s i n 55^{o} - c o s 35^{o} c o s 55^{o}$

(x) tan $48^{o} t a n 23^{o} t a n 42^{o} t a n 67^{o}$

(xi) $s e c 50^{o} s i n 40^{o} + c o s 40^{o} c o s e c 50^{o}$

cos (40^{\circ} + θ) - sin (50^{\circ} - θ) =

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