Solve x2-4 x-3-x3-6 x2-11 x-6-0

The correct option is A ( 3, 1)∪ (1,2)∪ (3,∞)Option (A) is the correct answer. Check the video for the approach. ...

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Quantitative Aptitude

Solving Inequalities

Solve x2+4 x+...

Question

Solve $\frac{x^{2} + 4 x + 3}{x^{3} - 6 x^{2} + 11 x - 6}$ > $0$

(- 3, - 1) \cup (1, 2) \cup (3, \infty)

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(- 3, - 1) \cup (1, 2)

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(- 3, \infty)

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(\infty, 3)

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Solution

The correct option is A $(- 3, - 1) \cup (1, 2) \cup (3, \infty)$
Option (A) is the correct answer. Check the video for the approach.

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Similar questions

Q. The expansion of

(x + 1) (x + 2) (x + 3)

is :

Q. Divide

x^{3} - 6 x^{2} + 11 x - 6

x^{2} + x + 1

Q. f(x) = x³ − 6x² + 11x − 6, g(x) = x² − 3x + 2

Question 24
Factorise
(i) $2 x^{3} - 3 x^{2} - 17 x + 30$

(ii) $x^{3} - 6 x^{2} + 11 x - 6$

(iii) $x^{3} + x^{2} - 4 x - 4$

(iv) $3 x^{3} - x^{2} - 3 x + 1$

Question 24
Factorise
(i) $2 x^{3} - 3 x^{2} - 17 x + 30$

(ii) $x^{3} - 6 x^{2} + 11 x - 6$

(iii) $x^{3} + x^{2} - 4 x - 4$

(iv) $3 x^{3} - x^{2} - 3 x + 1$

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Solve x2+4x+3x3−6x2+11x−6 > 0

The correct option is A (−3,−1)∪(1,2)∪(3,∞)Option (A) is the correct answer. Check the video for the approach.

Solve $\frac{x^{2} + 4 x + 3}{x^{3} - 6 x^{2} + 11 x - 6}$ > $0$

The correct option is A $(- 3, - 1) \cup (1, 2) \cup (3, \infty)$
Option (A) is the correct answer. Check the video for the approach.