Solve- x-4-2-2 x-3-3-5 x-32-2-x-9-3-

The correct option is B 16 x 4/2+2x 3/3=5x 32/2 x+9/3 Multiplying throughout by 6, we have 3(x 4) + 2(2x 3) = 3(5x 32) 2(x + 9) 3x 12 + 4x 6 = 15x 96 ...

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Standard VIII

Mathematics

Solving Equations Algebraically

Solve, x-4/2+...

Question

Solve, $\frac{x - 4}{2} + \frac{2 x - 3}{3} = \frac{5 x - 32}{2} - \frac{x + 9}{3}$ .

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Solution

The correct option is B
16

$\frac{x - 4}{2} + \frac{2 x - 3}{3} = \frac{5 x - 32}{2} - \frac{x + 9}{3}$
Multiplying throughout by 6, we have
$3 (x - 4) + 2 (2 x - 3) = 3 (5 x - 32) - 2 (x + 9)$
$3 x - 12 + 4 x - 6 = 15 x - 96 - 2 x - 18$
$∴$ $6 x = 96$
$∴$ $x = 16$ .

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Solve, x−42+2x−33=5x−322−x+93.

The correct option is B 16 x−42+2x−33=5x−322−x+93 Multiplying throughout by 6, we have 3(x−4)+2(2x−3) = 3(5x−32)−2(x+9) 3x−12+4x−6 = 15x−96−2x−18 ∴ 6x = 96 ∴ x=16.

Solve, $\frac{x - 4}{2} + \frac{2 x - 3}{3} = \frac{5 x - 32}{2} - \frac{x + 9}{3}$ .

The correct option is B
16

$\frac{x - 4}{2} + \frac{2 x - 3}{3} = \frac{5 x - 32}{2} - \frac{x + 9}{3}$
Multiplying throughout by 6, we have
$3 (x - 4) + 2 (2 x - 3) = 3 (5 x - 32) - 2 (x + 9)$
$3 x - 12 + 4 x - 6 = 15 x - 96 - 2 x - 18$
$∴$ $6 x = 96$
$∴$ $x = 16$ .