Solve, x−42+2x−33=5x−322−x+93.
20
16
15
10
x−42+2x−33=5x−322−x+93 Multiplying throughout by 6, we have 3(x−4)+2(2x−3) = 3(5x−32)−2(x+9) 3x−12+4x−6 = 15x−96−2x−18 ∴ 6x = 96 ∴ x=16.
Solve :- (3x2+5x−7)(x−1)−(x2−2x+3)(x+4)