Solve- x-4-3-2 x-3-35-5 x-32-9-x-9-28-

The correct option is B 19 x 4/3+2x 3/35=5x 32/9 x+9/28 Multiplying throughout by 9, we have 3x 12+18x 27/35=5x 32 9x+81/28 Transposing,18x 27/35+9x+81/28=2x 2 ...

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Byju's Answer

Standard VII

Mathematics

Rules for Elimination

Solve: x-4/3+...

Question

Solve: $\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}$ .

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Solution

The correct option is B
19

$\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}$
Multiplying throughout by 9, we have
$3 x - 12 + \frac{18 x - 27}{35} = 5 x - 32 - \frac{9 x + 81}{28}$
Transposing, $\frac{18 x - 27}{35} + \frac{9 x + 81}{28} = 2 x - 20$
Now clear of fractions by multiplying by $5 \times 7 \times 4$ = $140$ .
Thus, $72 x - 108 + 45 x + 405 = 280 x - 2800$
$∴$ $2800 - 108 + 405 = 280 x - 72 x - 45 x$
$∴$ $3097 = 163 x$
$∴$ $x = 19$ .

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Solve: x−43+2x−335=5x−329−x+928.

Solve: $\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}$ .