Solve- x-4-3-2x-3-35-5x-32-9-x-9-28-

X 4/3+2x 3/35=5x 32/9 x+9/28 Multiplying throughout by 9, we have 3x 12+18x 27/35=5x 32 9x+81/28 On transposing, 18x 27/35+9x+81/28=2x 20 LCM of 35 and 28 is ...

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Byju's Answer

Standard VIII

Mathematics

Variable and Constants

Solve, x-4/3+...

Question

Solve, $\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}$ .

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Solution

The correct option is B 19
$\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}$

Multiplying throughout by 9, we have
$3 x - 12 + \frac{18 x - 27}{35} = 5 x - 32 - \frac{9 x + 81}{28}$

On transposing,
$\frac{18 x - 27}{35} + \frac{9 x + 81}{28} = 2 x - 20$

LCM of 35 and 28 is 140
Thus, $72 x - 108 + 45 x + 405 = 280 x - 2800$
$\Rightarrow 2800 - 108 + 405 = 280 x - 72 x - 45 x$
$\Rightarrow 3097 = 163 x$
$\Rightarrow x = 19$ .

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Similar questions

Q. Solve,

\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}

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\frac{x - 4}{3} = \frac{5 x - 32}{9}

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Solve, x−43+2x−335=5x−329−x+928.

The correct option is B 19x−43+2x−335=5x−329−x+928 Multiplying throughout by 9, we have 3x−12+18x−2735=5x−32−9x+8128 On transposing, 18x−2735+9x+8128=2x−20 LCM of 35 and 28 is 140 Thus, 72x–108+45x+405=280x–2800 ⇒ 2800–108+405=280x–72x–45x ⇒ 3097=163x ⇒ x=19.

Solve, $\frac{x - 4}{3} + \frac{2 x - 3}{35} = \frac{5 x - 32}{9} - \frac{x + 9}{28}$ .