Question

Solve graphically.

Express answers in both inequality and interval notation.

$x^2+5x\le 0$

Answer 1

$x^2+5x\le 0$

$x(x+5)\le 0$

	x<-5	x=-5	-5<x<0	x=0	x>0
x+5	-	0	+	+	+
x	-	-	-	0	+
x(x+5)	+	0	-	0	+

$-5\le x\le 0$

Interval notation $[-5,0]$