Question

Solve graphically.

Express answers in both inequality and interval notation.

$x^2+6x\ge 0$

Answer 1

$x^2+6x\ge 0$

$x(x+6)\ge 0$

	x<-6	x=-6	-6<x<0	x=0	x>0
x+6	-	0	+	+	+
x	-	-	-	0	+
x(x+6)	+	0	-	0	+

$x\le -6,x\ge 0$

Interval notation $(-\infty ,-6]\cup [0,\infty )$