Question

Solve graphically.

Express answers in both inequality and interval notation.

$x^2+7x+10>0$

Answer 1

$x^2+7x+10>0$

$(x+2)(x+5)>0$

	x<-5	x=-5	-5<x<-2	x=-2	x>-2
x+2	-	-	-	0	+
x+5	-	0	+	+	+
(x+2)(x+5)	+	0	-	0	+

$x<-5,x>-2$

Interval notation $(-\infty ,-5)\cup (-2,\infty )$