Question

Solve graphically.

Express answers in both inequality and interval notation.

$x^2+x<12$

Answer 1

$x^2+x<12$

$x^2+x-12<0$

$(x-3)(x+4)<0$

	x<-4	x=-4	-4<x<3	x=3	x>3
x+4	-	0	+	+	+
x-3	-	-	-	0	+
(x-3)(x+4)	+	0	-	0	+

$-4<x<3$

Interval notation $(-4,3)$