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Question

# Solve graphically the pair of linear equations: 4x−3y+4=0,4x+3y−20=0. Find the area of the region bounded by these lines and x-axis

A
12 sq. units
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B
18 sq. units
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C
9 sq. units
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D
13 sq. units
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Solution

## The correct option is A 12 sq. units4x−3y+4=0⟹x=−4+3y4Let, y=4, then x=−4+3(4)4=2Similarly, when y=0,x=−14x+3y−20=0⟹x=20−3y4Let, y=4, then x=20−3(4)4=2Similarly, when y=0,x=5Plotting the above points on the graph, we get, the intersecting point i.e(2,4)Area of the region bounded by these lines and x-axis =12×6units×4 units=12 sq. units.

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