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Question

Solve
I=121+4x4x2dx

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Solution

@page { margin: 2cm } p { margin-bottom: 0.25cm; line-height: 120% }

12(x2x214)dx121(x22.x12+14224)dx121 (112)2(x12)2dx12⎢ ⎢ ⎢ ⎢ ⎢1112sin1⎢ ⎢ ⎢ ⎢ ⎢x12112⎥ ⎥ ⎥ ⎥ ⎥⎥ ⎥ ⎥ ⎥ ⎥122sin1(2x122)+C


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