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Question

Solve
I=x+2x2+5x+6dx

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Solution

We have,
I=x+2x2+5x+6dx
I=x+2x2+3x+2x+6dx
I=x+2(x+3)(x+2)dx
I=1(x+3)dx
on Integrating and we get,
I=log(x+3)+c 1xdx=log2
Hence, this is the answer.

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