Solve:
$i) n + 5 = 19$
$i i) 4 p - 3 = 13$

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Solution

$i) n + 5 = 19$

$n = 19 - 5 = 14$

$i i) 4 p - 3 = 13 \Rightarrow 4 p = 16$

$p = \frac{16}{4} = 4$

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Similar questions

\frac{3 - \sqrt{5}}{3 + 2 \sqrt{5}} = a \sqrt{5} - \frac{19}{11}

\frac{x}{3} + \frac{y}{4} = 4; \frac{x}{2} - \frac{y}{4} = 1

\frac{x}{3} + 5 y = 13; 2 x + \frac{y}{2} = 19

\frac{2}{x} + \frac{3}{y} = 13; \frac{5}{x} - \frac{4}{y} = - 2

4 x - 19 y + 13 = 0, 13 x - 23 y = - 19

b

\frac{b}{13} = 7

Solve:

log (5x + 19) = log( 7x + 3)

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