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Question

SOLVE:

If 2a+b=11 and ab=24 , find the value of 4a²+b².

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Solution

Given that :-
2a + b = 11
and
ab = 24

Now ,
( 2a + b ) = 11

Squaring both sides , we get
( 2a + b ) ² = 121
=> 4a² + b² + 4ab = 121

putting the value of ab here , we get
=> 4a² + b² + 4 * 24 = 121
=> 4a² + b² + 96 = 121
=> 4a² + b² = 121 - 96
=> 4a² + b² = 25

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