Question

Solve
If a = 0.1039, then the value of $\sqrt{4a^2-4a+1}+3a$ is:

Answer 1

$\sqrt{4a^2-4a+1}+3a=\sqrt{(1{)}^2+(2a{)}^2-2\times 1\times 2a}+3a=\sqrt{(1-2a{)}^2}+3a=(1-2a)+3a=(1+a)=(1+0.1039)=1.1039$