1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Mathematics
Word Problems in Addition and Subtraction
Solve in posi...
Question
Solve in positive integers:
41
x
+
47
y
=
2191
.
A
x
=
40
,
y
=
33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x
=
50
,
y
=
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x
=
12
,
y
=
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x
=
71
,
y
=
19
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
x
=
50
,
y
=
3
We will go by options
Let
x
=
50
and
y
=
3
⇒
41
(
50
)
+
47
(
3
)
=
2191
satisfied the equation
Suggest Corrections
0
Similar questions
Q.
9, 4x-3y = 33x-5y = 71
Q.
Solve the following systems of equations:
2
x
+
3
y
=
1
60
x
+
40
y
=
19
,
x
≠
0
,
y
≠
0
Q.
If
41
x
+
31
y
=
18
and
31
x
+
47
y
=
60
then find the value of
x
+
y
.
Q.
Solve for x and y:
x
+
y
−
8
2
=
x
+
2
y
−
14
3
=
3
x
+
y
−
12
11
Q.
On solving
31
x
+
47
y
=
15
and
47
x
+
31
y
=
63
,
we get:
(a) x = 2, y = −1
(b) x = −2, y = 1
(c) x = 1, y = 2
(d) x = 3, y = −2
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Multiplication and Division of Linear Equations
MATHEMATICS
Watch in App
Explore more
Word Problems in Addition and Subtraction
Standard VIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app