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Byju's Answer
Standard XII
Mathematics
Special Integrals - 1
Solve ∫0[1]...
Question
Solve
∫
[
1
]
0
3
x
3
[
x
]
d
x
, where [.] denotes greatest integer function.
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Solution
∫
[
1
]
0
3
x
3
[
x
]
d
x
∫
log
3
2
0
3
x
d
x
+
∫
1
log
3
2
3
x
d
x
2
=
[
3
x
l
n
3
]
log
3
2
0
+
[
3
x
2
l
n
3
]
1
log
3
2
=
2
l
n
3
−
1
l
n
3
+
3
2
l
n
3
−
1
l
n
3
=
7
2
l
n
3
−
2
l
n
3
=
3
2
l
n
3
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