Solve ∫10(x2+1)dx
Consider the given integral.
I=∫10(x2+1)dx
I=[x33+x]10
I=[133+1−0]
I=43
Hence, this is the answer.
Solve the following
1. -5(a-3)-2(a+5)=7-9a
2. m/7+1/3= m/6+5/4
3. 2a/3-4/5=-3/4+1