The correct option is D 43 Consider the given integral. #10; #10; I=∫_0^1( x^2+1 )dx #10; #10; I=[ x^33+x ]_0^1 #10; #10; I=[ 1^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definite Integral as Limit of Sum

Solve ∫01 x...

Question

Solve $\int_{0}^{1} (x^{2} + 1) d x$

\frac{5}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{4}{3}$
Consider the given integral.

$I = \int_{0}^{1} (x^{2} + 1) d x$

$I = {[\frac{x^{3}}{3} + x]}_{0}^{1}$

$I = [\frac{1^{3}}{3} + 1 - 0]$

$I = \frac{4}{3}$

Hence, this is the answer.

Suggest Corrections

Similar questions

\int_{0}^{1} \frac{x^{2} - 2}{x^{2} + 1} d x

[\frac{4}{5} + {\frac{3}{5} + (\frac{2}{5} - \frac{1}{6})} + \frac{1}{2}] - \frac{2}{3}

Solve the following

1. -5(a-3)-2(a+5)=7-9a

2. m/7+1/3= m/6+5/4

3. 2a/3-4/5=-3/4+1

(4^{0} + 5^{- 1}) \times 5^{2} \times \frac{1}{3}

(2^{- 1} + 3^{- 1} + 4^{- 1}) \times \frac{3}{4}

\frac{4}{3}

\frac{2}{3}

\frac{1}{5}

Join BYJU'S Learning Program