Question

Solve
${\int }_0^1(x^2+3x+2)dx=$

Answer 1

$\begin{array}{c}{\int }_0^1\left(x^2+3x+2\right)dx\\ \Rightarrow {\left[\frac{x^3}{3}+\frac{3x^2}{2}+2x\right]}_0^1\\ \Rightarrow \frac{{\left(1\right)}^3}{3}+\frac{3{\left(1\right)}^2}{2}+2\times 1-0-0-0\\ \Rightarrow \frac{1}{3}+\frac{3}{2}+2=\frac{2+9+12}{6}\\ =\frac{23}{6}\end{array}$