Question

Solve:

$\int 2^{(3x+4)}dx=$?

• A. $\frac{3}{\left(\log 2\right)}.2^{(3x+4)}+c$
• B. $\frac{2^{(3x+4)}}{3\left(\log 2\right)}+c$
• C. $\frac{2^{(3x+4)}}{3\left(\log 3\right)}+c$
• D. None of these

Answer 1

Answer: (B)

$\frac{2^{(3x+4)}}{3\left(\log 2\right)}+c$

$\int 2^{(3x+4)}dx=\int 2^{3x}\times 2^{4}dx$

$=2^4\int 2^{3x}dx$

$=2^4\frac{2^{3x}}{3\log 2}+C$

$=\frac{2^{(3x+4)}}{3\left(\log 2\right)}+C$