wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve:
1a2x2=12aloga+xax

Open in App
Solution

We have,

I=dxa2x2

I=dx(xa)(x+a)

I=12a[dx(xa)dx(x+a)]

I=12a[ln(xa)ln(x+a)]+C

I=12a[ln|x+a|ln|xa|]+C

I=12a[ln|a+x|ln|ax|]+C

I=12a[lna+xax]+C

Hence, proved.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon