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Algebra of Limits

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Question

Solve:
$\int \frac{1}{e^{x} + e^{- x}} d x$

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Solution

$\begin{matrix} W e h a v e I = \int \frac{1}{e^{x} + e^{- x}} d x = \int \frac{e^{x}}{1 + e^{2 x}} d x = {tan}^{- 1} (e^{x}) + c . \end{matrix}$

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