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Question

Solve :
1+xcosxx(1x2e2sinx)dx=knx2e2sinx1x2e2sinx+C then k is equal to :

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Solution

1+xcosxx(1x2e2sinx)dxputxesinx=tesinx(1+xcosx)dx=dt=dtt(1t2)=logt12log(1t)12log(t+1)+C=12(log(t21+t2))+C=12log(x2e2sinx1x2e2sinx)+CK=1

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