Question

Solve ${\int }^{}\frac{\sin 2xdx}{\sin 5x.\sin 3x}$

Answer 1

$\int \frac{\sin 2xdx}{\sin 5x\sin 3x}$

$\int \frac{\sin \left(5x-3x\right)dx}{\sin 5x\sin 3x}$

$\int {\left(\frac{\sin 5x\cos 3x}{\sin 5x\sin 3x}-\frac{\cos 5x\sin 3x}{\sin 5x\sin 3x}\right)}^{dx}$

$\int \cot 3xdn-\int \cot 5xdx$

$\frac{1}{3}log\sin 3x-\frac{1}{5}\log \sin 5n+c$