Question

Solve: $\int (\sec x+\tan x{)}^{2}dx=$?

Answer 1

$=\int ({\sec }^{2}x+2\sec x\tan x+{\tan }^{2}x)dx$
$=\int (2{\sec }^{2}x+2\sec x\tan x+1)dx$
$=2\tan x+2\sec x+x+C$