wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve:

x2/3(1+x5/3)133dx

A
925(1+x5/3)103+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
915(1+x5/3)103+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
950(1+x5/3)103+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C
950(1+x5/3)103+C

We have,
I=x2/3(1+x5/3)133dx

Let
t=1+x5/3

dtdx=0+53x2/3

3dt5=x2/3 dx

Therefore,
I=35t133dt

I=35t103103+C

I=950(1+x5/3)103+C

I=950(1+x5/3)103+C

Hence, this is the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression - Sum of n Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon