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Question
Solve it:-
−4∫dt√t4−1
−4∫dt√t4−1
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Solution
−4∫dt√t4−1=−4∫dt√t3=−4∫t−32dt=−4⎡⎢
⎢
⎢⎣t−32+1−32+1⎤⎥
⎥
⎥⎦+c=−4×2−1t−12+c=8√t+c
−4∫dt√t4−1
=−4∫dt√t3
=−4∫t−32dt
=−4⎡⎢
⎢
⎢⎣t−32+1−32+1⎤⎥
⎥
⎥⎦+c
=−4×2−1t−12+c
=8√t+c
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