Solve- nbsp- nbsp-2-5-2-8- - 2-72-10-2-6-2-10-2-4-

The correct option is C 2^ 10 (2^5)/(2^8)× (2^ 7) =(2^5)× (2^ 7)/(2^8) =(2^5+( 7))/(2^8) nbsp; nbsp; [∵ a^m nbsp;× a^n = a^m+n] = nbsp; (2^5 7)/(2^ ...

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Byju's Answer

Standard VII

Mathematics

Quotient Law of Exponent

Solve:- nbs...

Question

Solve:-

$(\frac{2^{5}}{2^{8}}) \times 2^{- 7}$

$2^{10}$

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$2^{6}$

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$2^{- 10}$

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$2^{- 4}$

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Solution

The correct option is C
$2^{- 10}$

$\frac{(2^{5})}{(2^{8})} \times (2^{- 7})$

$= \frac{(2^{5}) \times (2^{- 7})}{(2^{8})}$

$= \frac{(2^{5 + (- 7)})}{(2^{8})}$ $[∵ a^{m} \times a^{n} = a^{m + n}]$

$= \frac{(2^{5 - 7})}{(2^{8})}$

$= \frac{(2^{- 2})}{(2^{8})}$

$= 2^{(- 2 - 8)}$ $[∵ a^{m} \div a^{n} = a^{m - n}]$

$= 2^{- 10}$

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\frac{5 x - 4}{6} = 4 x + 1 - \frac{3 x + 10}{2}

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\frac{2^{- 3} \times 5^{- 3} \times 10^{2} \times 25}{5^{4} \times 2^{- 5}}

Solve:-

$(\frac{2^{5}}{2^{8}}) \times 2^{- 7}$

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(2^{3} \times 2^{5}) \div 2^{8}

Q. 25^102-4^102 is divisible by a.21 b.25 c.29 d.30

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Solve:- (2528)×2−7

The correct option is C 2−10 (25)(28)× (2−7) =(25)× (2−7)(28) =(25+(−7))(28) [∵am×an = am+n] =(25−7)(28) =(2−2)(28) =2(−2−8) [∵am÷an = am−n] =2−10

Solve:-

$(\frac{2^{5}}{2^{8}}) \times 2^{- 7}$