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Question

Solve (1+exy)dx+exy(1xy)dy=0

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Solution

Given (1+ex/y)dx+ex/y(1xy)dy=0

(1+ex/y)dxdy+ex/y(1xy)=0

Put x=vydxdy=v+ydvdy

(1+ev)(v+ydvdy)+ev(1v)=0

dyy=(1+ev)(v+ev)dv

Integrating, we get
ln y=ln(v+ev)+ln c

ln[y(xy+exy)]=ln c

x+y ex/y=c

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