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Byju's Answer
Standard IX
Mathematics
Normal Form to Standard Form
Solve 1+ e ...
Question
Solve
(
1
+
e
x
y
)
d
x
+
e
x
y
(
1
−
x
y
)
d
y
=
0
Open in App
Solution
Given
(
1
+
e
x
/
y
)
d
x
+
e
x
/
y
(
1
−
x
y
)
d
y
=
0
⇒
(
1
+
e
x
/
y
)
d
x
d
y
+
e
x
/
y
(
1
−
x
y
)
=
0
Put
x
=
v
y
⇒
d
x
d
y
=
v
+
y
d
v
d
y
(
1
+
e
v
)
(
v
+
y
d
v
d
y
)
+
e
v
(
1
−
v
)
=
0
⇒
d
y
y
=
−
(
1
+
e
v
)
(
v
+
e
v
)
d
v
Integrating, we get
ln
y
=
−
l
n
(
v
+
e
v
)
+
l
n
c
⇒
l
n
[
y
(
x
y
+
e
x
y
)
]
=
l
n
c
⇒
x
+
y
e
x
/
y
=
c
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0
Similar questions
Q.
Solve
(
1
+
e
x
/
y
)
d
x
+
e
x
/
y
(
1
−
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y
)
d
y
=
0
Q.
Solve
(
1
+
e
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/
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)
d
x
+
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(
1
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)
d
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using
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.
Q.
(
1
+
e
x
y
)
d
x
+
e
x
y
(
1
−
x
y
)
d
y
=
0
is homogeneous equation
Q.
The solution of
⎛
⎜
⎝
1
+
e
x
y
⎞
⎟
⎠
d
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+
e
x
y
(
1
−
x
y
)
d
y
=
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is
Q.
Find the solution of
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1
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d
y
=
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