Solve : $(3 - \frac{x^{3}}{6}) 7$

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Solution

Let the given equation

$(3 - \frac{x^{3}}{6}) 7$

According to the $B O D M A S$

First, we simplify which is in the bracket.

$= (\frac{18 - x^{3}}{6}) 7$

Then open the bracket

$= \frac{18 \times 7 - x^{3} \times 7}{6}$

$= \frac{126 - 7 x^{3}}{6}$

So, according to $B O D M A S$ the above equation can be written as
$\frac{126 - 7 x^{3}}{6}$

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