( 32^15)^ 2 + 4 = ( ( 2^5)^15)^ 2 + 4 = ( 2 )^ 2 + 4 = 14 + 4 = 1 + 164 = 174 ...

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Algebra of Complex Numbers

Solve :- 32...

Question

Solve :-
${⎛ ⎜ ⎝ 32^{\frac{1}{5}} ⎞ ⎟ ⎠}^{- 2} + 4$

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Solution

${⎛ ⎜ ⎝ 32^{\frac{1}{5}} ⎞ ⎟ ⎠}^{- 2} + 4 = {⎛ ⎜ ⎝ {(2^{5})}^{\frac{1}{5}} ⎞ ⎟ ⎠}^{- 2} + 4$
$= {(2)}^{- 2} + 4$
$= \frac{1}{4} + 4 = \frac{1 + 16}{4} = \frac{17}{4}$

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Similar questions

32^{1 / 5}

{log}_{1 / 3} (2 {(\frac{1}{2})}^{x} - 1) = {log}_{1 / 3} ({(\frac{1}{4})}^{x} - 4)

Find:
(i) $64^{\frac{1}{2}}$ .

32^{\frac{1}{5}}

Find:

(i) (ii) (iii)

32^{\frac{1}{5}}

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