CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Determinant

Solve | [ ...

Question

Solve
$∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & - 1 6 & 4 & - 5 - 4 & - 2 & 3 \end{matrix} ∣ ∣ ∣ ∣$

Open in App

Solution

$∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & - 1 6 & 4 & - 5 - 4 & - 2 & 3 \end{matrix} ∣ ∣ ∣ ∣$

$= 1 (12 - 10) - 1 (18 - 20) - 1 (- 12 + 16)$

$= 2 + 2 - 4 = 0$

Suggest Corrections

thumbs-up

0

Similar questions

Q. State the properties & solve :

1) \frac{18}{23} \times (\frac{4}{9} \times \frac{6}{7}) = (\frac{18}{23} \times \frac{4}{9}) \times \frac{6}{7}

2) \frac{16}{17} \times (\frac{3}{4} + \frac{20}{31}) = (\frac{16}{17} \times \frac{3}{4}) + (\frac{16}{17} \times \frac{20}{31})

Q. Solve the equation:

5 x + 2 \frac{3}{5} = 9 - \frac{4}{5} x

Q. Solve the following:

\frac{4 \frac{3}{5}}{\frac{23}{10}}

4 \frac{3}{5} \times 2 \frac{3}{7} = \frac{23}{5} \times \frac{17}{7} = ?

1 \frac{4}{5} - 2 \frac{3}{4}

\frac{8}{11} + \frac{3}{8} + \frac{9}{10}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon